ARITHMETIC SERIES PROGRAM IN C + +

Arithmetic series in mathematics is a sequence of numbers where the next number is the previous number with the addition of a number is a specific difference. Examples are 3,5,7,9,11,13, ..... Arithmetic series can be expressed by the following formula:
                  a, a + b, a + 2b, a + 3b, ...

• Print Series Arithmetic Algorithms
       cetak_aritmatika procedure (input / output x: array, input: a, input: b, input: n)

    Declaration:
        i: integer

   Description:
      read a, b, n
      x [1] <= a
      x [2] <= a + b
         for i = 3 to n do
             x [i] <= a + (b * i)
            end for
         for i = 1 to n do
        write x [i]
   end for

• Algorithm Finding nth
       suku_n procedure (input: a, input: b, input: n, output: un)

    Declaration:
       a, b, n, un: Integer

    Description:
       read a, b, n
       un <= a + (n-1) * b
      write un

• Finding Algorithm amount of all ethnic
      jumlah_n procedure (input: a, input: b, input: n, output: sn)

    Declaration:
        a, b, n, sn: integer

    Description:
       read a, b, n
       sn <= (n / 2) * (2 * a + (n-1) * b)
       write sn

Program Runs Arithmetic

# Include <cstdlib>
# Include <iostream>

using namespace std;
arithmetic class {
    friend istream & operator>> (istream &, arithmetic &);
    friend ostream & operator <<(ostream &, arithmetic &);

public:
   arithmetic ();
   void print ();
   void interest ();
   void sum ();

private:
   int x [100];
   int a, b, n, un, sn;
   };

istream & operator>> (istream & mlebu, arithmetic & s) {
      court <<"Enter Interest First:"; mlebu>> S.A;
      court <<"Enter the difference:"; mlebu>> s.b;
      court <<"Enter the Number of Interest:"; mlebu>> sn; court <<endl;
      mlebu return;
      }

ostream & operator <<(ostream & metu, arithmetic & v) {
      metu <<"Interest First:" <<v.a <<endl;
      metu <<"Difference:" <<v.b <<endl;
      metu <<"Number of Interest:" <<v.n <<endl;
      metu <<"Arithmetic Series:";
      for (int i = 0; i <v.n; i + +) {
        metu <<v.x [i ]<<",";}
          metu <<endl;
          metu <<"Number of Interest The n:" <<v.un <<endl;
          metu <<"Number of All Tribes:" <<v.sn <<endl;
          metu return;}
      
arithmetic: arithmetic () {
    court <<"\ t \ tSlamet Icelandic Al Hidayah" <<endl;
    court <<"\ t \ t 10018075" <<endl;
    court <<endl;
    court <<"PRINTING AND COUNTING PROGRAM RUNS Arithmetic" <<endl;
    court <<endl;
    }

void arithmetic:: print () {
    x [0] = a;
    x [1] = a + b;
    for (int i = 2; i <n; i + +) {
       x [i] = a + (b * i);}
       }
      
void arithmetic:: tribe () {
    int t;
    court <<"Enter Interest Want In looking for:"; cin>> t;
    un = a + (t-1) * b;}
      
void arithmetic:: sum () {
    sn = (n / 2) * (2 * a + (n-1) * b);}
      
int main (int argc, char * argv [])
{
  arithmetic x;
  cin>> x;
  x.cetak ();
  x.suku ();
  x.jumlah ();
  court <<x;
  court <<endl;
    
system ("PAUSE");
return EXIT_SUCCESS;
}

Output :

Well that's the program that I can make,,,,,!

If there are less jelass know any mistake, do not hesitate to leave a comment ataun advice. So that I can fix it later terimakasihh over his visit,,

Regards super ..

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